Before stopping bike covers distance of 12 m. Bike running at speed of 60 km/h needs to apply instant brakes to stop. In other words, motion at constant acceleration. This section is about solving problems relating to uniformly accelerated motion. More specifically, the equations of motion describe the behavior of a physical system as a set of mathematical functions in terms of dynamic variables. In this section we examine equations that can be used to describe motion. In physics, equations of motion are equations that describe the behavior of a physical system in terms of its motion as a function of time. We have looked at describing motion in terms of words and graphs. ∴ s = 60 + 0.6 × 2.56 = 92.16 m 3 rd equation of motionġ.) Third equation of motion relates the initial velocity, final velocity, acceleration and displacement.Ģ.) Using graphical method, 3 rd equation of motion is derived as,ģ.) Third equation is very useful in finding the displacement, acceleration, initial velocity and final velocity.Ĥ.) Eg. In this section we will look at the third way to describe motion. What is the distance of boundary from the batting crease?Īns: u = 30 m/s, t = 1.6 sec, a = 1.2 m/s 2 The Third equation of motion is known as the velocity-position relation or velocity-displacement relation and is given by. Batsman hits the ball towards boundary at speed of 30 m/s and uniform acceleration of 1.2 m/s 2 takes 1.6 seconds cross the boundary rope. Difference between 2nd and 3rd equation of motion 2 nd equation of motionġ.) Second equation of motion gives the relation between initial velocity, displacement and acceleration of object.Ģ.) Using graphical method, 2 nd equation of motion is derived as,ģ.) Second equation is very useful in finding the displacement, acceleration, initial velocity and time.Ĥ.) Eg.
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